Question

AJUTORRRRRR
ESTE URGENT​

Answer 1

fractii cu acelasi numitor ⇒ se aduna numaratorii

$\dfrac{2}{3} + \dfrac{4}{3} + \dfrac{1}{3} + \dfrac{3}{3} = \dfrac{2+4+1+3}{3} = \bf \dfrac{10}{3}=3\dfrac{1}{3}$

$\dfrac{5}{6} + \dfrac{2}{6} + \dfrac{1}{6} + \dfrac{3}{6} = \dfrac{5+2+1+3}{6} = \bf \dfrac{11}{6} = 1\dfrac{5}{6}$

$\dfrac{1}{2}+\dfrac{2}{2}+\dfrac{4}{2}+\dfrac{3}{2}=\dfrac{1+2+4+3}{2}=\bf\dfrac{10}{2} = 5$

$\dfrac{5}{8}+\dfrac{1}{8}+\dfrac{3}{8}+\dfrac{2}{8}=\dfrac{5+1+3+2}{8}= \bf \dfrac{11}{8} = 1\dfrac{3}{8}$

$\dfrac{20}{100}+\dfrac{11}{100}+\dfrac{30}{100}+\dfrac{24}{100} = \dfrac{20+11+30+24}{100} = \bf\dfrac{85}{100}$

$\dfrac{3}{5} + \dfrac{1}{5} + \dfrac{2}{5} + \dfrac{4}{5} = \dfrac{3+1+2+4}{5} = \bf \dfrac{10}{5}=2$