Question

Ajutorrrrrrrr repede

Answer 1

Răspuns:

Explicație pas cu pas:

2 sau 6

Answer 2

$\it x^2+2x-8=0 \Rightarrow x^2+2x+1-9=0 \Rightarrow (x+1)^2-3^2=0 \Rightarrow \\ \\ \Rightarrow (x+1-3)(x+1+3)=0 \Rightarrow (x-2)(x+4)=0 \Rightarrow x_1=-4,\ x_2=2\\ \\ \\ AB=|x_2-x_1|=|2-(-4)|=|2+4|=|6|=6$