Question

Alchenle obtinute prin deshidratarea alcoolilor cu formula moleculara C4H10O se oxideaza cu K2Cr2O7(H2SO4) .Separat se oxideaza in aceleasi conditii alcoolii. Stiind ca se utilizeaza 4 moli amestec echimolecular de alcooli cu formula de mai sus , care este raportul volumelor de solutie K2Cr2O7 1/3 M utilizate pentru oxidarea alchenelor si alcoolilor?

Answer 1

CH3-CH2-CH2-CH2-OH→ CH3-CH2-CH=CH2 + H2O

CH3-CH (OH) -CH2-CH3 → CH3-CH =CH-CH3+2H2O

CH3-CH(CH3) -CH2-OH→ (CH3)2C=CH2 + H2O

CH3-C(OH) (CH3) -CH3 → (CH3)2C=CH2 + H2O

 

CH3-CH2-CH2-CH2-OH + [O]→ CH3-CH2-CHO + H2O

CH3-CH (OH) -CH2-CH3 + [O]→ CH3-CO –CH2-CH3+H2O

CH3-CH(CH3) -CH2-OH+ [O]→ CH3-CH(CH3) - CHO + H2O

CH3-C(OH) (CH3) -CH3 + [O]→ -

3 moli [O]

 

CH3-CH2-CH=CH2 +5[O]→ CH3-CH2-COOH + CO2 + H2O

CH3-CH =CH-CH3+4[O]→ CH3-COOH +HOOC-CH3

(CH3)2C=CH2 + 4[O]→ (CH3)2CO+CO2 +H2O

(CH3)2C=CH2 + 4[O]→ (CH3)2CO+CO2 +H2O

17 moli [O]

Se determina volumul solutiei de K2Cr2O7 folosita la oxidarea alcoolilor

1 mol………………3 moli

K2Cr2O7 + H2SO4 → 3[O]

x                               3 moli

x=1 mol K2Cr2O7

 

1L solutie………………..1/3 moli

V1 L solutie……………..1 mol

V1=3L solutie

Se determina volumul solutiei de K2Cr2O7 folosita la oxidarea alchenelor

1 mol………………3 moli

K2Cr2O7 + H2SO4 → 3[O]

x                               17 moli

x=17/3 moli K2Cr2O7

 

1L solutie………………..1/3 moli

V2 L solutie……………..17/3 mol

V2=17 L solutie

 V1/V2 = 3/17