Question

alfa numărul necunoscut 5+[16-(9:a×8+7)]×6=4:(1×2)+3×3​

Answer 1

Răspuns:

5+[16-(9:a×8+7)]×6=4:(1×2)+3×3

5+[16-(9:ax8+7)]X6=4:2+9

5+[16-(9:ax8+7)]X6=2+9

5+[16-(9:ax8+7)]X6=11

[16-(9:ax8+7)]X6=11-5

[16-(9:ax8+7)]X6=6

[16-(9:ax8+7)]=6:6

16-(9:ax8+7)=1

(9:ax8+7)=16-1

9:ax8+7=15

9:ax8=15-7

9:ax8=8

9:a=8:8

9:a=1

a=9:1

a=9