Question

Am nevoie acum de ele cine ma poate ajuta?

Answer 1

Răspuns:

Explicație pas cu pas:

m )  log_3[5×6:10]=log_3[30:10]=log_3{3}=1

n)log_2[5×12:30]=log_2[60:20]=log_2[2]=1

o)log_5[18:2]/log_5[3]=log_5[3²}/log_5{3}=2

p} log_3[2:4³]/log_3[28:7]=log_3{2^(-5)]/log_3[2²]=-5/2

q) log_3[27]-log_√3[27]-log_1/3[27]

formula de trecere la alta baza   log_a[b]=log_b[√b]/log_b[a]

log_√3[27]=log_3[27]/log_3[√3]=3/1/2=6

log_1/3[27]=log_3[27]/log_3[1/3]=3/(-1)=-3  revenim la ex

=3-6-(-1)=4-6=-2