Question

Am nevoie de ajutor la aceasta problema!

Answer 1

 $-( \sqrt{15} -1)$ ≤ x - 2 ≤ $\sqrt{15} -1$ /+2
-$\sqrt{15} +3 \leq x \leq \sqrt{15} +1$⇒
x∈{1,2,3,4}⇒ card M= 4

Answer 2

[tex]\it |x-2| \leq\sqrt{15}-1 \ \textless \ \sqrt{16} - 1 =4-1=3 \Rightarrow |x-2| \ \textless \ 3\Rightarrow \\\;\\ \Rightarrow -3\ \textless \ x-2 \ \textless \ 3 |_{+2} \Rightarrow -1\ \textless \ x\ \textless \ 5 \ \ \ \ \ (1) \\\;\\ x\in \mathbb{Z}^* \ \ \ \ (2)[/tex]


$\it (1),\ (2) \Rightarrow x\in\{1,\ 2,\ 3,\ 4\}$


$\it M = \{1,\ 2,\ 3,\ 4\} \Rightarrow card(M) =4.$