Question

Am nevoie de ajutor la acest ex la mateee ​

Answer 1

A.

${(2x + 1)}^{2} - {(x - 1)}^{2} + (x - 2)(x + 2) - 3 {x}^{2} + 14 = \\ 4 {x}^{2} + 4x + 1 - ( {x}^{2} - 2x + 1) + {x}^{2} - 4 - 3 {x}^{2} + 14 \\ 2{x }^{2} + 4x + 11 - {x}^{2} + 2x - 1 = \\ x ^{2} + 6x + 10$

B.

$e(x) = x {}^{2} + 6x + 10 \\ = > e(x) = {x}^{2} + 3 \times 2 \times x + {3}^{2} + 1 = > \\ e(x) = {(x + 3)}^{2} + 1 \\ {(x + 3)}^{2} \geqslant 0 \\ 1 \geqslant 0 \\ = > e(x) \geqslant 0$