Question

am nevoie de ajutor la exercițiul 5​

Answer 1

Răspuns:

$a)(7 \times (14 - 2 \times 7) \div 2) ^{2} = (7 \times (14 - 14) \div 2) ^{2} = \\ = {(7 \times 0 \div 2})^{2} = (0 \div 2) ^{2} = {0}^{2} = 0$

$b)( {10}^{2} - {8}^{2} ) \div 6 \div 2 + {1}^{2019} = \\ = (100 - 64) \div 6 \div 2 + 1 = \\ = 36 \div 6 \div 2 + 1 = 6 \div 2 + 1 = 3 + 1 = 4$

$c)(17 \times (25 - 8 \times 3) \times {1}^{2021} - 15) \times {2}^{3} - {2}^{2} \times 3 = \\ = (17 \times (25 - 24) \times 1 - 15) \times 8 - 4 \times 3 = \\ = (17 \times 1 - 15) \times 8 - 4 \times 3 = \\ = 2 \times 8 - 4 \times 3 = 16 - 12 = 4$

$d)(( {9}^{2} - {2}^{4} \times 5 ) \div 1 + {5}^{9} \div ( {5}^{2} ) ^{4} ) \times {2}^{2} = \\ = ((81 - 16 \times 5) + {5}^{9} \div {5}^{8} ) \times 4 = \\ = ((81 - 80) + 5) \times 4 = \\ = (1 + 5) \times 4 = 6 \times 4 = 24$

$e)(((169 \div 13 - {2}^{3} ) \div 5 + (7 \times {2}^{3} - 2 \times 3) \div 5 + {2}^{3} ) \div 19 + 5) \times {2}^{3} - {2}^{4} \times 3 = \\ = (((13 - 8) \div 5 + (7 \times 8 - 6) \div 5 + 8) \div 19 + 5) \times 8 - 16 \times 3 = \\ = (((5 \div 5 + (56 - 6) \div 5 + 8) \div 19 + 5) \times 8 - 48 = \\ = ((1 + 50 \div 5 + 8) \div 19 + 5) \times 8 - 48 = \\ = ((1 + 10 + 8) \div 19 + 5) \times 8 - 48 = \\ = (19 \div 19 + 5) \times 8 - 48 = \\ = (1 + 5) \times 8 - 48 = 6 \times 8 - 48 = 48 - 48 = 0$

$f)( {3}^{32} \div {3}^{2} + {2}^{2} \times {2}^{25} - {2019}^{0} ) \div ( {27}^{10} + {8}^{9} - 324 \div {18}^{2} ) = \\ ( {3}^{30} + {2}^{27} - 1) \div (( {3}^{3} ) ^{10} + ( {2}^{3} ) ^{9} - 324 \div 324) = \\ = ( {3}^{30} + {2}^{27} - 1) \div ( {3}^{30} + {2}^{27} - 1) = 1$

Answer 2

$\bf a)\ \ \it [7\cdot(14-2\cdot7):2]^2=(7\cdot0:2)^2=0^2=0\\ \\ \bf b)\ \ \it (10^2-8^2):6:2+1^{2019}= (100-64):6:2+1=6:2+1=4\\ \\ \bf c)\ \ \it =(17\cdot1-15)\cdot8-4\cdot3=16-12=4$