Question

am nevoie de ajutor neapărat!! ​

Answer 1

Hei! :)

$a) 2(3x-2)+4(4-2x)=\\=6x-4+16-8x=\\=12-2x$

$b) 3(1-5x)-2(2x-1)=\\=3-15x-4x+2=\\=5-19x$

$c) (x-2y)(2x+y)=\\=2x^{2} +xy-4xy-2y^{2} =\\=2x^{2} -2y^{2} -3xy$

$d) (x+3)(4x-1)=\\=4x^{2} -x+12x-3=\\=4x^{2} +11x-3$

$e)(x-2)(2x+1)-(2x-3)(1-3x)=\\=2x^{2} -x-4x-2-2x+6x^{2} +3-9x=\\=8x^{2} -16x+1$

$f) x*x+x^{2} *x^{2} -x^{4}:x^{2} =\\=x^{2} +x^{4} -x^{2} =\\=x^{4}$

$g) (2x+1)^{2} -(1-2x)^{2} =\\=4x^{2} +4x+1-1+4x-4x^{2} =\\=8x$

$h) (x^{2} -x+1)(x^{2} +x+1)=\\=x^{4} +x^{3} +x^{2} -x^{3} -x^{2} -x+x^{2} +x+1=\\=x^{4} +x^{2} +1$