Question

Am nevoie de ajutor va rog!​

Answer 1

Stim ca orice numar la puterea 0(inafra de 0) = 1

=> la numarator 1-1+$4^1^4$ = $4^1^4$

=> $\frac{2^{2^{14}}}{2^{3^{8}}} = \frac{2^{28}}{2^{24}} = 2^{28-24}=2^{4}=16$

Aici trebuia sa stii niste formule

Answer 2

Răspuns:

16

Explicație pas cu pas:

$\dfrac{1 - {15}^{0} + {4}^{14} }{ {8}^{8} } = \dfrac{1 - 1 + {( {2}^{2} )}^{14} }{ {( {2}^{3} )}^{8} } = \\ = \dfrac{{2}^{2 \cdot 14}}{{2}^{3 \cdot 8}} = \dfrac{{2}^{28}}{{2}^{24}} = {2}^{28 - 24} = {2}^{4} = 16$