Matematică, întrebare adresată de mariangaming131, 8 ani în urmă

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Anexe:

Răspunsuri la întrebare

Răspuns de dariusbarbu
11

Răspuns:

  • \boxed{\bf{c) \:  \frac{1}{a} }}
  • \boxed{\bf{d) a - b}}

Explicație pas cu pas:

\bf{c) \: ( \frac{a}{a - 1}  +  \frac{1}{a + 1}  +  \frac{2}{ {a}^{2}  - 1}  -  \frac{2a}{(a - 1)(a + 1)} ) \div  \frac{a {}^{3 }  + a}{ {a}^{2} - 1 }  }

\bf{( \frac{a}{a - 1} +  \frac{1}{a + 1}  +  \frac{2}{(a - 1)(a + 1)}   -  \frac{2a}{(a - 1)(a + 1)}) \times  \frac{a {}^{2} - 1 }{a {}^{3} + a }  }

\bf{( \frac{a \times (a + 1) + a - 1 + 2}{(a - 1)(a + 1)} -  \frac{2a}{(a - 1)(a + 1)} ) \times  \frac{(a - 1)(a + 1)}{a(a { }^{2} + 1) }  }

\bf{( \frac{a {}^{2} + 2a + 1 }{(a - 1)(a + 1)} -  \frac{2a}{(a - 1)(a + 1)}  ) \times  \frac{(a - 1)(a + 1)}{a(a {}^{2} + 1) } }

\bf{( \frac{(a + 1) {}^{2} }{(a - 1)(a + 1)} -  \frac{2a}{(a - 1)(a + 1)} ) \times  \frac{(a - 1)(a + 1)}{a(a {}^{2} + 1) }  }

\bf{( \frac{(a + 1) {}^{2} }{(a - 1)(a + 1)} -  \frac{2a}{(a - 1)(a + 1)} ) \times  \frac{(a - 1)(a + 1)}{a( {a}^{2}  + 1)} }

\bf{( \frac{a + 1}{a - 1}   - \frac{2a}{(a - 1)(a + 1)} ) \times  \frac{(a - 1)(a + 1)}{a(a {}^{2} + 1) } }

\bf{ \frac{(a + 1) {}^{2}  - 2a}{(a - 1)(a + 1)} \times  \frac{(a - 1)(a + 1)}{a(a {}^{2}  + 1)}  }

\bf{ \frac{a {}^{2} + 2a + 1 - 2a }{a + 1} \times  \frac{a + 1}{a(a {}^{2} + 1) }  }

\bf{ \frac{a {}^{2} + 1 }{a + 1}  \times  \frac{a + 1}{a(a {}^{2} + 1) }  =  \:\boxed{\bf{ \frac{1}{a} }}}

\bf{d) \: (a  -  \frac{4ab}{a + b}   + b) \div ( \frac{a}{a + b} -  \frac{b}{b - a}  -  \frac{2ab}{a {}^{2} - b {}^{2}  } ) }

\bf{ \frac{a(a + b) - 4ab + b(a + b)}{a + b}  \div ( \frac{a}{a + b}   - \frac{b}{ - (a - b)}  -  \frac{2ab}{(a - b)(a + b)} )}

\bf{ \frac{a {}^{2}  + ab - 4ab + ab + b {}^{2} }{a + b}  \div ( \frac{a}{a + b}  +  \frac{b}{a - b}  -  \frac{2ab}{(a - b)(a + b)} )}

\bf{ \frac{a {}^{2} - 2ab + b {}^{2}  }{a + b}  \div  \frac{a(a - b) + b(a + b) - 2ab}{(a - b)(a + b)} }

\bf{ \frac{(a - b) {}^{2} }{a + b} \div  \frac{a {}^{2}  - ab + ab + b {}^{2}  - 2ab}{(a - b)(a + b)}  }

\bf{ \frac{(a - b) {}^{2} }{a + b} \div  \frac{a {}^{2} - 2ab + b {}^{2}  }{(a - b)(a + b)}  }

\bf{ \frac{(a - b) {}^{2} }{a + b}  \div  \frac{(a - b) {}^{2} }{(a - b)(a + b)} = \frac{(a - b) {}^{2} }{a + b} \div  \frac{a - b}{a + b}   }

\bf{ \frac{(a - b) {}^{2} }{a + b} \times  \frac{a + b}{a - b}   =  \boxed{\bf{a - b}}}

Bafta ! :)


mariangaming131: Mersii mult
math86: Frumoasă rezolvare!
dariusbarbu: Multumesc ! :)
math86: =)
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