Question

am nevoie de exercitiul 6 pana la ora 20!!!​

Answer 1

Răspuns:

<A=80° <B=14°=><C=180-(80+14)=86°

<CAA'=80:2=40°

<ACC'=86:2=43°

<ABB'=14:2=7°

<BIC=180-(7+43)=180-50=130°

b)<CAA'=34°. <ACC'=44°. =>

<A=34×2=68°

<C=44×2=88°

<B=180-(68+88)=180-156=24°

<AIB=180-(A/2+B/2)=180-(34+12)=

180-46=134°