Question

Am nevoie de raspuns la 5.Ajutați-mă!!Dau 25 puncte și coroana!!!RAPID

Answer 1

Răspuns:

5. sin B= AC/BC  => BC= AC/sin 60= 8* $\frac{2}{\sqrt{3} }$= $\frac{16 \sqrt{3} }{3}$cm

cos B= AB/BC=>   AB= BC* cos 60 = $\frac{16 \sqrt{3} }{3}$ * $\frac{1}{2}$ = $\frac{8 \sqrt{3} }{3}$ cm

$AC^{2}$= CD*BC  => CD= 64* $\frac{ 3}{16 \sqrt{3}}$ = 4*3 / $\sqrt{3}$= 12

$AB^{2}$= BD*BC => BD= $\frac{64*3}{9}$ * $\frac{ 3}{16 \sqrt{3}}$ = $\frac{4}{\sqrt{3} }$= $\frac{4\sqrt{3} }{3}$ cm

$AD^{2}$= CD* BD= $\frac{4\sqrt{3} }{3}$ * $4\sqrt{3}$ = 16* 3/3 = 16 cm

AD= $\sqrt{16}$= 4 cm