Question

am nevoie de rezolvare.$\int \frac{ x^{2} }{x+1} dx$

Answer 1

Adui  si  scazi  1  la  numarator  .Obtii
(x²-1+1)/(x+1)=(x²-1)/(x+1+1/(x+1)=  x-1+1/(x+1)
Integrezi
∫(x-1+1/(x+1)]dx=∫xdx-∫dx+∫dx/(x+1)=x²/2-x+ln(x+1)+C