Question

Am nevoie de rezolvarea lui a)

Answer 1

conform Viete, x1=x2+...+x5= -(-a)/1=a
a=5
asta e tot la a)

Extra
b)
x^4-x³-x+1=0
x³(x-1)-(x-1)=0
(x³-1)(x-1)=0
(x-1) (x²+x+1) (x-1)=0
(x-1)²(x²+x+1)=0
x1=x2=1∈R, radacina dubla

x²+x+1=0
x3,4=-1/2+-i√3/2=α si αconjugat∈C