Question

Am nevoie de un raspuns urgent va rog dau coroana

Answer 1

Răspuns:

$tg^{2} (t)=\frac{sin^{2} (t)}{cos^{2} (t)} =\frac{sin^{2} (t)}{1-sin^{2} (t)}\\=>sin^{2} (t)=\frac{tg^{2} (t)}{1+tg^{2} (t)} \\=>|sin(t)|=\sqrt{\frac{tg^{2} (t)}{1+tg^{2} (t)} } = \sqrt{\frac{4/25}{1+4/25}} =\sqrt{\frac{4}{29} }$