Question

Am nevoie doar de 4 va rog

Answer 1

 

 

Ex. 4.

$\displaystyle\bf\\m_a=\frac{\dfrac{^{3)}2}{~~3}+\dfrac{48}{9}}{2}=\frac{\dfrac{6}{9}+\dfrac{48}{9}}{2}=\frac{~~\dfrac{54}{9}~~}{2}=\frac{6}{2}=\boxed{\bf3\in N}$