Question

am nevoie la p 2. va rog mult ofer 78p

Answer 1

a/7 supraunitara => a>7 dar a ∈ ℕ=> A= {8,9,10,11,...}
12/b subunitara => b<12 dar b ∈ ℕ-{0} => B= {11,10,9,...,1}

A ∩ B = {x | x ∈ A şi x ∈ B} => A ∩ B = {8,9,10,11}