Question

Am nevoie neaparat va rog

Answer 1

Răspuns:

Explicație pas cu pas:

6a) (3x -1) >(-2)(-3)

3x -1 > 6, 3x > 7,  x > 7/3

b) (2x -3x +3)/6 < 1/4

4(-x +3) < 6,  -4x < 3 |*-1,   x > -3/4

c) (√3 -√5)x > √5 -√3

-(√5 -√3 )x > √5 -√3 |*-1

(√5 -√3 )x < √3 -√5 = -(√5 -√3)

x < -1

7a) 5x -0,5 <= 0

5x <= 1/2,  10x < 1,  x < 1/10

b) -2/(x-1) >= 0

x-1 < 0,  x < 1

c) -x +2 < 0,  -x < -2 |*-1,   x > 2