Question

am nevoie urgent de rezolvare la problema 2​

Answer 1

Răspuns: a) AB=AC⇒∡ABC=∡ACB=(180°-∡BAC)÷2=75°

b) D-sim.(B,AC)⇒BD⊥AC si BM≡MD

∡AMB=∡AMD=90°

AM-lat.com.

de aici⇒ΔAMB≡AMD⇒AB=AD

                                        ∡BAM=∡DAM=30°

∡BAD=∡BAM+∡DAM=30°+30°=60°(1)

AB≡AD(2)

din (1) si (2)⇒ΔABD-echilateral

c)ΔBMC≡ΔDMC⇒BC≡CD

⇒(prin cazul L.L.L)ΔABC≡ΔADC