Question

Am si eu nevoie de ajutor, va rog!
X-3 supra 8 + X-9 supra 12 = 3X+7 supra 20 +3

Answer 1

$\frac{x-3}{8}+ \frac{x+9}{12}= \frac{3x+7}{20}+3$
Aducem la același numitor, care este 120.
[tex] \frac{15x-45}{120}+ \frac{10x+90}{120}= \frac{18x+42}{120}+ \frac{360}{120} \\ 15x-45+10x+90=18x+42+360 \\ 25x+45=18x+402 \\ 25x-18x=402-45 \\ 7x=357 \\ x=357:7 \\ x= 51 [/tex]