Question

am tema la chimie va rog ajutor
Calculati numarul de moli si atomi din:
80g HE
1600g S
420g Ce
Restu in poza

Answer 1

Răspuns:

Explicație:

a.

nr. moli si nr. atomi

80g He

n= m : M

n= 80g : 4g/moli= 20 moli He

1mol He-------6,022.10²³atomi He

20 moli ------------------x

x= 20 . 6,022.10²³= 120,440 .10²³atomi He

1600g S

n=1600g : 32g/moli=50 moli S

1mol S------6,022.10²³S

50moli-----------y

y= 50 . 6,022.10 ²³=301,1 .10²³atomi S

420g Cl

n= 420g : 71g/moli= aproximativ  6 moli Cl2

1mol Cl2 ---------2 .6,022.10²³atomi Cl

6moli-------------------z

z= 6 . 2 . 6,022.10²³ = 72,264 .10²³atomi Cl

b.

nr. atomi si mase

5moli Na

1mol Na------------6,022.10²³Na

5moli------------------x

x= 5 . 6,022.10²³=30,11 .10²³atomi Na

m= n . M

m= 5moli . 23g/moli= 115g Na

2kmoli F2  = 2000moli F2

1mol F2---------2 .6,022.10 ²³atomi F

2000 moli---------------y

y= 2000. 2 . 6,022.10²³=24088 .10²³atomi F

m= 2000moli. 2 .19g/moli= 76000 g= 76kg F

0,04 moli Ca

1mol Ca----------6,022.10²³Ca

0,04moli---------z

z= 0,04 . 6,022.10²³= 0,24088.10²³atomi Ca

m= 0,04moli. 40g.moli= 1,60 g Ca

c.

masa si nr. moli

60,22.10la 25= 6022.10²³

n =6022.10²³: 6,022.10²³=1000moli N2

m= 1000moli. 28g/moli= 28000g=28kg N

24,088 . 10la21 = 0,24088.10 ²³

n= 0,24088.10²³ : 6,022.10²³=0,04 moli O2

m= 0,04moli .32g/moli  =1,28 g O

n= 48,176.10²³ : 6,022.10²³ = 8moli C

m= 8moli. 12g/moli= 96g C