Question

Aplica Legea Conservării Masei Substantelor la următoarele reacții chimice:
1) S+Hg= HgS
2) Mg+O=MgO
3) NaOH+FeCl3=NaCl+Fe(OH)3
4)N2+H2=NH3
DAU COROANA ! URGEEEEEEENT

Answer 1

Răspuns:

1) S + Hg = HgS

HgS = 233 g/mol

S = 32 g/mol

Hg = 201 g/mol

32 + 201 = 233

233 = 233 (A)

2) 2Mg + O2 = 2MgO

Mg = 24 g/mol

O = 16 g/mol

MgO = 40 g/mol

2 × 24 + 2× 16 = 2 × 40

48 + 32 = 80

80 = 80 (A)

3) 3NaOH + FeCl3 = 3NaCl + Fe(OH)3

NaOH = 40 g/mol

FeCl3 = 162.5 g/mol

NaCl = 58.5 g/mol

Fe(OH)3 = 107 g/mol

3 × 40 + 162.5 = 3 × 58.5 + 107

120 + 162.5 = 175.5 + 107

282.5 = 282.5 (A)

4) N2 + 3H2 = 2NH3

N = 14 g/mol

H = 1 g/mol

NH3 = 17 g/mol

2 × 14 + 3 × 2 × 1 = 2 × 17

28 + 6 = 34

34 = 34 ( A )