Question

aplificaţi raportului algebric √3x -4 pe √3x+4 cu 4-√3x

Answer 1

$\frac{ \sqrt{3} - 4}{ \sqrt{3} x + 4} = \frac{ \sqrt{3} - 4}{4 + \sqrt{3} x} = \frac{( \sqrt{3} - 4)(4 - \sqrt{3} x)}{(4 + \sqrt{3} x)(4 - \sqrt{3} x)}$

$= \frac{4 \sqrt{3} - \sqrt{9} x - 16 + 4 \sqrt{3} x}{ {4}^{2} - {( \sqrt{3} x)}^{2} } = \frac{ 4 \sqrt{3} - 3x - 16 + 4 \sqrt{3} x}{16 - 3 {x}^{2} }$