Question

Arata ca 3*2^10+3*2^11=pp

Answer 1

3*2^10+3*2^11=

3×2^10 × ( 1 + 2) =

3 × 2^10 ×3 =

3^2 × (2^5)^2 = > patrat perfect

Answer 2

3*$2^{10}$+3*$2^{11}$=

3*$2^{10}$(1+2)=3*$2^{10}$*3=$3^{2}$*$(2^{5})^{2}$=pp