Question

aratati ca 1/2³ + 2/3³ + 5/6³ = 1
Rapid va rog
dau coroana ​

Answer 1

Răspuns:

Explicație pas cu pas:

$\Big( \frac{1}{2} \Big) ^{3} + \Big( \frac{2}{3} \Big) ^{3} + \Big( \frac{5}{6} \Big) ^{3}$

$=\frac{1 {}^{3} }{2 {}^{3} } + \frac{ {2}^{3} }{ {3}^{3} } + \frac{ {5}^{3} }{ {6}^{3} }$

$= \frac{ {}^{27)} 1}{8} + \frac{ {}^{8)} 8}{27} + \frac{125}{216}$

$=\frac{27 + 64 + 125}{216}= \frac{216}{216} = \bf{} 1$

Answer 2

Răspuns:

Explicație pas cu pas:

asa cum ai scris (doar cu numitorii la cub) egalitatea nu este adevarata

1/2³ + 2/3³ + 5/6³ = 1

1/8 + 2/27 + 5/216 = 27/216 + 16/216 + 5/216 = 48/216

______________

Daca era toata fractia la cub:

(1/2)³ + (2/3)³ + (5/6)³ = 1

1/8 + 8/27 + 125/216 = 27/216 + 64/216 + 125/216 = 216/216 = 1