Question

Aratati ca media aritmetica a numerelor x=4-3(a-2) si y=2(a+1)+a e un numar natural,pentru orice numar a real
Va rog ajutati-ma

Answer 1

Ma=(x+y)/2

x=4-3(a-2)=4-3a+6=2-3a
y=2(a+1)+a=2a+2+a=3a+2

Ma=(2-3a+3a+2)/2=4/2=2

Ma=2, oricare ar fi ''a''.

Answer 2

X= 4-3(a-2) => x= 4-3a+6 Y=2(a+1)+a => y= 2a+2+a =>y= 3a+2 Ma= x+y/2=> Ma= 4-3a+6+3a+2/2 =>Ma= 4+6+2/2 (deoarece -3a si 3a se reduc) => Ma = 12/2=> Ma = 6