Question

arătați ca nr N =2 la puterea 0 + 2 la puterea 1 + 2 la puterea 2 + 2 la puterea 3 + ....+2la puterea 9 ajutor ofer coroana !!!!!!

Answer 1

N=2∧0+2∧1+2∧3+.........+2∧9=[2∧(9+1)-1]/2-1=2∧10-1=1024-1=1023
Am calculat dupa formula 1+a+a∧2+a∧3+......+a∧n=[a∧(n+1)-1]/a-1