Question

aratati ca numarul A=(a,bc+b,ca+c,ab cu bara deasupra):1,11

Answer 1

A=a+b/10 + c/100 + b + c/10 + a/100 + c + a/10 + b/100

A=(a+b+c)+ (a+b+c)1/10 + (a+b+c)1/00

A=(a+b+c)(1+1/10 + 1/100) = (a+b+c)111/100

deci A se divide cu 1,11