Question

Aratati ca numarul n = (radical din 3 -1 )^2 + 2 radical din 3

Answer 1

[tex]n=( \sqrt{3} -1)^2+2 \sqrt{3} \\ n= \sqrt{3} ^2-2 \sqrt{3}*1+1^2+2 \sqrt{3} \\ n=3+1\\ n=4[/tex]