Question

Aratati ca numarul natural a=27^5*9^7*3^9+(3^13)^3 este patrat perfect



DAU COROANA!!REPEDE PLS

Answer 1

[tex]a=27^5*9^7*3^9+(3^{13)}^3\\ a=(3^3)^5*(3^2)^7*3^9+3^{13*3}\\ a=3^{15}*3^{14}*3^9+3^{39}\\ a=3^{15+14+9}+3^{39}\\ a=3^{38}+3^{39}\\ a=3^{38}*(1+3)\\ a=(3^{19})^2*2^2\\ a=(3^{19}*2)^2p.p.[/tex]