Question

Aratati ca radical din 3(2radical din 3+1)-radical din 3=6. Va rog rezolvarea completa!!!

Answer 1

$\sqrt{3}$* ($2\sqrt{3}$+1)-$\sqrt{3}$=

$\sqrt{3}$*$2\sqrt{3}$+$\sqrt{3}$*1-$\sqrt{3}$=2*3+$\sqrt{3}$-$\sqrt{3}$=6+0=6

Answer 2

√3(2√3+1)-√3=

=2×3+√3-√3=

=6+√3-√3=6