Question

Aratati ca
$(\frac{4}{3 } + \frac{3}{4} ) \div (\frac{4 }{3 } - \frac{3}{4 }) \times \frac{7}{2} = 1$
​

Answer 1

$( \frac{4}{3} + \frac{3}{4}) \div ( \frac{4}{3} - \frac{3}{4} ) \times \frac{7}{2} = 1$

$\frac{ \frac{16}{12 } + \frac{9}{12} }{ \frac{4}{3} - \frac{3}{4} } \times ( \frac{7}{2} ) = 1$

$\frac{ \frac{16 + 9}{12} }{ \frac{4}{3} - \frac{3}{4} } \times ( \frac{7}{2} ) = 1$

$\frac{ \frac{25}{12} }{ \frac{4}{3} - \frac{3}{4} } \times ( \frac{7}{2} ) = 1$

$\frac{ \frac{25}{12} }{ \frac{16}{12} - \frac{9}{12} } \times \frac{7}{2} = 1$

$\frac{ \frac{25}{12} }{ \frac{16 - 9}{12} } \times ( \frac{7}{2} ) = 1$

$\frac{ \frac{25}{12} }{ \frac{7}{12} } \times ( \frac{7}{2} ) = 1$

$\frac{25}{12} \times ( \frac{12}{7} ) \times ( \frac{7}{2} ) = 1$

$\frac{25 \times 12}{12 \times 7} = \times ( \frac{7}{2} ) = 1$

$\frac{25}{7} \times ( \frac{7}{2} ) = 1$

$\frac{25 \times 7}{7 \times 2} = 1$

$\frac{25}{2} = 1$

$\frac{25}{2} = \frac{2}{2}$

Sper ca ti-am fost de folos. Succes!!!