Question

aratati ca tg 60°/ctg 60°•cos 45°=√2.Va rog mult!!!!!​

Answer 1

$\it ctgx=\dfrac{1}{tgx}\\ \\ \\ \dfrac{tg60^o}{ctg60^o}=\dfrac{tg60^o}{\dfrac{1}{tg60^o}}=tg60^o:\dfrac{1}{tg60^o}=tg60^o\cdot \dfrac{tg60^o}{1}= \\ \\ \\ =tg60^o\cdot tg60^o=\sqrt3\cdot\sqrt3=3\\ \\ \\ cos45^o=\dfrac{\sqrt2}{2}$