Question

Arati ca 36^{log in baza6 din 5 } +10^{1-lg2} -3^{log in baza 9 din 36} =24

Answer 1

$36^{log_65}+10^{1-lg2}-3^{log_936}=6^{2log_65} +10^{lg10-lg2}-9^{\frac12log_936}=$

$=6^{log_65^2}+10^{lg\frac{10}{2}}-9^{log_9\sqrt{36}}=25+5-6=24$