Question

As vrea o rezolvare completa.

Answer 1

2/(√3 - 1) - √3 = {2 - √3 (√3 - 1)}//(√3 - 1) = ( 2 - 3 + √3)/(√3 - 1);

(√3 - 1)/(√3 - 1) = 1

Answer 2

    
[tex]\displaystyle \\ \frac{2}{ \sqrt{3}-1 } -\sqrt{3} = \frac{2}{ \sqrt{3}-1 } - \frac{\sqrt{3}(\sqrt{3}-1 )}{ \sqrt{3}-1 } = \\ \\ \\ =\frac{2-\sqrt{3}(\sqrt{3}-1 ) }{ \sqrt{3}-1 } = \frac{2-(3-\sqrt{3}) }{ \sqrt{3}-1 } = \\ \\ \\ = \frac{2-3+\sqrt{3} }{ \sqrt{3}-1 } = \frac{-1+\sqrt{3} }{ \sqrt{3}-1 } = \frac{\sqrt{3} -1 }{ \sqrt{3}-1 } = \boxed{1 } \\ \\ \texttt{cctd}[/tex]