Question

Asa e facuta si cu rezultatul

Answer 1

[tex]2^{2x+5}+2^{2x+4}-2^{2x+3}-2^{2x+2}+2^{2x+1}+2^{2x}=624\\ 2^{2x}\cdot 2^5+2^{2x}\cdot 2^4-2^{2x}\cdot 2^3-2^{2x}\cdot2^2+2^{2x}\cdot2+2^{2x}\cdot1=624\\ 2^{2x}(2^5+2^4-2^3-2^2+2+1)=624\\ 2^{2x}(32+16-8-4+2+1)=624\\ 2^{2x}\cdot 39=624\\ 2^{2x}=16\\ 2^{2x}=2^4\\ 2x=4\Rightarrow x=2[/tex]