Question

Asupra unsui resort elastic actioneaza o forta de 20 N . Resortul se alungeste cu 4 cm . Determina constanta elastica a resortului

Answer 1

$F_e=20 \ N \\ \triangle l=4 \ cm=0,04 \ m \\ \boxed{k-?} \\ \bold{Rezolvare:} \\ \boxed{k= \frac{F_e}{\triangle l} } \\ k= \frac{20 \ N}{0,04 \ m } \\ \Rightarrow \boxed{k= 500 \ N/kg}.$

Answer 2

Se da:
F=20N
Δl=4cm=0,04m
Sa se afle: K=? N/m
Rezolvare: K= F/Δl
Calcule: K=20N : 0,04m =500 N/m.