Question

Avand la dispozitie HCL 37% (ρ=1,19 g/ cm^{3} ) sa se prepare 500 ml solutie HCL 2N (mase atomice: H-1 Cl-35,4)

Answer 1

solutia finala :  Vs = 0,5 l   cN = 2 val/l ⇒ e = 1 echivalentHCl  md =36,4g
solutia initiala : md = 36,4g  c = 37% ⇒  msi = 98,378 g  ⇒ Vs = 82,67 ml
peste 82,67 ml solutie 37% se adauga 417,33ml apa