Question

(b•3+6)+b+(b•3+6-b):2=79

Answer 1

(bx3+6)+b+(bx3+6-b):2=79

(3b+6+b+3b+6-b):2=79

(6b+12):2=79

6b+12=2x79

6b+12=158

6b=158-12

6b=146 , impartim la 2 si partea stanga si partea dreapta

3b=73

b=73:3

b= 24,3