Question

| b) 4x³ - 9 - 2(2x - 3);
e) 16x³ + 16x² - 9x - 9;
c) 4x³ + 4x² -9(x + 1);
f)4x³- 4x²- 25x + 25​

Answer 1

Răspuns:

Explicație pas cu pas:

$b) 4x^3-9-2(2x-3)=4x^3-9-4x+6=4x^3-4x-3 \\\texttt{Nu se poate descompune mai departe.}$

$e)16x^3+16x^2-9x-9=16x^2(x+1)-9(x+1)=(x+1)(16x^2-9)=\\=(x+1)(4x-3)(4x+3)\\c)4x^3+4x^2-9(x+1)=4x^2(x+1)-9(x+1)=(x+1)(4x^2-9)=\\=(x+1)(2x-3)(2x+3)\\f)4x^3-4x^2-25x+25=4x^2(x-1)-25(x-1)=(x-1)(4x^2-25)=\\=(x-1)(2x-5)(2x+5)$