Question

b) va rog..............rapidd..................

Answer 1

$| \sqrt{2} - 1 | = \sqrt{2} - 1 \\ | \sqrt{2} - 2| = 2 - \sqrt{2} \\ |2 \sqrt{2} - 3 | = 3 - 2 \sqrt{2} \\ ( \frac{ \sqrt{2} - 1}{3} + \frac{2 - \sqrt{2} }{6} + \frac{3 - 2 \sqrt{2} }{12} ) \\ \div ( - 5 \times \frac{1}{10} ) = \\ \frac{4 \sqrt{2 } - 4 + 4 - 2 \sqrt{2} + 3 - 2 \sqrt{2} }{12} \\ \div ( - \frac{1}{2} ) = \frac{1}{4} \times ( - 2) = - \frac{1}{2}$