Question

B = X E R/ RADICAL DIN (2X-5) LA PUTEREA 2 < 11

Answer 1

Explicație pas cu pas:

$\sqrt{ {(2x - 5)}^{2} } < 11 \iff |2x - 5| < 11$

$- 11 < 2x - 5 < 11$

$- 6 < 2x < 16$

$- 3 < x < 8$

$x \in \Big( - 3 ; 8\Big)$