Question

b) x² - 12x + 35 = 0​

Answer 1

x²-12x+35=0

{a=1

{b=-12

{c=35

∆=b²-4ac=(-12)²-4•1•35=144-140=4

✓∆=✓4=2

$\bf x1 = \frac{ - b - \sqrt{∆} }{2a} = \frac{12 - 2}{2} = \frac{10}{2} = 5$

$\bf x2 = \frac{ - b + \sqrt{∆} }{2a} = \frac{12 + 2}{2} = \frac{14}{2} = 7$

S={5;7}

Answer 2

x²-5x-7x+35=0

x(x-5)-7(x-5)=0

(x-5)(x-7)=0

x-5=0

x-7=0

x=5

x=7