Matematică, întrebare adresată de RanchidaSan, 8 ani în urmă

Buna, ma puteti ajuta va rog?​

Anexe:

Răspunsuri la întrebare

Răspuns de Seethh
1

\dfrac{14\dfrac{1}{6}-0,0025\cdot25 }{4\dfrac{1}{4}:0,85+1:0,5 } :0,2+\bigg(4\dfrac{1}{8} -0,004\cdot300\bigg):0,015=\\\\\\=\dfrac{\dfrac{14\cdot6+1}{6}-\dfrac{25}{10000}  \cdot25}{\dfrac{4\cdot4+1}{4}:\dfrac{85}{100} +1:\dfrac{5}{10}  } :\dfrac{2}{10}+\bigg(\dfrac{4\cdot8+1}{8}-\dfrac{4}{1000}\cdot300\bigg):\dfrac{15}{1000}=

=\dfrac{\dfrac{85}{6} -\dfrac{625}{10000} }{\dfrac{17}{4}\cdot\dfrac{100}{85} +1\cdot\dfrac{10}{5}  }\cdot\dfrac{10}{2} +\bigg(\dfrac{33}{8}-  \dfrac{1200}{1000}  \bigg)\cdot\dfrac{1000}{15}=

=\dfrac{\dfrac{85}{6}-\dfrac{1}{16}  }{\dfrac{1700}{340}+2 }\cdot5+\bigg(\dfrac{33}{8}-\dfrac{6}{5}\bigg)\cdot\dfrac{200}{3} =\dfrac{\dfrac{680-3}{48} }{5+2}\cdot5+\dfrac{165-48}{40}\cdot\dfrac{200}{3}=\\\\\\=\dfrac{\dfrac{677}{48} }{7} \cdot 5+   \dfrac{117}{40} \cdot\dfrac{200}{3}=\dfrac{677}{48}\cdot \dfrac{1}{7}\cdot5+\dfrac{23400}{120} =\dfrac{3385}{336}+\dfrac{23400}{120}=  \dfrac{68905}{336}


RanchidaSan: Mersi mult!
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