Question

Buna neata! Ajutati-ma va rog! Stiind ca X+4·Y+2·Z= 13 si 3·X+2·Z= 11, determinati Z+Y+Z. va rog repede! Dau funda!!!

Answer 1

$x+4y+2z=13 \\ 3x+2z=11\ \ \ \ \ \ \ \ adunam\ \ cele\ \ doua\ \ relatii \\ ========== \\ 4x+4y+4z=24\ \ /:4=>\boxed{x+y+z=6}$

Answer 2

x+4y+2z=13
3x+2z=11
________________
4x+4y+4z=24⇒4(x+y+z)=24⇒x+y+z=24:4
                                             x+y+z=6