Question

buna ,poate cineva sa ma ajute 
nu stiu cum se logaritmeaza si am E1 : 2a , E2 : 3ab ,E3: $\frac{4ab}{3c}$
multumesc oricum

Answer 1

Folosim relatiile:[tex]log_{c}(a \cdot b)= log_{c}a+log_{c}b\\ log_{c}( \frac{a}{b} )= log_{c}a-log_{c}b[/tex]
[tex]log_{n}E_1=log_{n}(2a)=log_{n}2+log_{n}a\\ log_{n}E_2=log_{n}(3ab)=log_{n}3+log_{n}a+log_{n}b\\ log_{n}E3=log_{n}( \frac{4ab}{3c} )=log_{n}4ab-log_{n}3c=\\ log_{n}4+log_{n}a+log_{n}b-log_{n}3-log_{n}c[/tex]