Question

Bună seara , am nevoie de ajutor : Sa se imparta numarul 1268 in parti invers proportionale cu numerele 2/3 ; 3/4 ; 4/5 ;5/6

Answer 1

a+b+c+d=1268
2a/3=3b/4=4c/5=5d/6=k
a=3k/2
b=4k/3
c=5k/4
d=6k/5


3k/2+4k/3+5k/4+6k/5=1268
90k+80k+75k+72k=1269×60
317k=1268×60
k=4÷60=240


a=3×240/2=360
b=4×240/3=320
c=5×240/4=300
d=6×240/5=288
...............................

total = 1268