Question

Calcul pas cu pas ???

Answer 1

$\int_{-1}^{0} (x+3) dx = (\frac{1}{2}x^2+3x) |_{-1}^{0} = \frac{1}{2}0^2 - 3 \cdot 0 -  (\frac{1}{2}(-1)^2+3(-1)) = -(\frac{1}{2} - 3) = \frac{5}{2}$