Question

Calculati [1,1(6) + 1 intreg si 1/4 : 0,(3)] * (2-4/3)^2

Answer 1

 [1,1(6) + 1 intreg si 1/4 : 0,(3)] * (2-4/3)²=
1,1(6)=(116-11)/90=105/90=21/30=7/6
0,(3)=3/9=1/3
= [7/6 + 5/4 : 1/3] * [(6-4)/3]²=
= [7/6 + 5/4 ×3] * (2/3)²=
= (7/6 + 15/4) * 4/9=
= (7*2+15*3)/12 * 4/9=
= 59/12 * 4/9=
= 59/27=2,(185)